SOLUTION: 2x^2+7x-5 = x^2+6x+7

Question 347025: 2x^2+7x-5 = x^2+6x+7

Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

This is a quadratic equation. So we want one side e4qual to zero. I'll start by subtracting the entire right side of the equation from both sides:

giving us:

Now we factor (or use the Quadratic Formula). This factors pretty easily. The factors of -12 that add up to 1 are 4 and -3:

From the Zero Product property we know that this (or any) product can be zero only if one (or more) of the factors is zero. So:
x+4 = 0 or x-3 = 0
Solving these we get:
x = -4 or x = 3
These are the solutions to your equation.
RELATED QUESTIONS
6x+7=3x-11 12x-(7x-6)=41 2(5x-8)=-6(x-8) -2x-5+4x=7=6x... (answered by rfer)

6x+5=7x-2 (answered by cleomenius)

(4x^5 + 7x^4 - 3x^2 + 9) + (6x^5 -8x^4 + 2x^3 -... (answered by jim_thompson5910)

2x-7+6x=57 x= -54=-7x+x+6 x= x+2+7x=18 x= 2x+9=x+14 x= 10+2x=-4x+46 x=... (answered by College Student)

1.) 3x/(x+1) + 6/2x = 7/x 2.) 6x/(x+4) + 4 = 2x+2/(x-1) 3.) 7x+1/2x+5 + 1 =10x-3/3x (answered by stanbon)

2x^3-x^2-6x/2x^2-7x+6 (answered by Earlsdon,oberobic)

Please help me solve this equation:... (answered by solver91311)

Multiply. State any restrictions on the variable. x^2+6x-7/x^2+5x times... (answered by jim_thompson5910)

Multiply. State any restrictions on the variable x^2+6x-7/x^2+5x times... (answered by jim_thompson5910)