SOLUTION: Determine the nature of the solutions of the equation.
x^2-14x+49=0
What does the equation have?
One real solution, two non-real solutions, or two real solutions
Algebra.Com
Question 342464: Determine the nature of the solutions of the equation.
x^2-14x+49=0
What does the equation have?
One real solution, two non-real solutions, or two real solutions
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use the discriminant.
There is one real solution (a double root).
.
.
.
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