SOLUTION: I know that the fomula x= -b/2a is used to solve for the minimum/maximum value of a quadratic formula but what happens when the quadratic formula is {{{ y= -6x^2-1 }}} a= -6 b=0(?
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Question 341980: I know that the fomula x= -b/2a is used to solve for the minimum/maximum value of a quadratic formula but what happens when the quadratic formula is a= -6 b=0(?) c= -1. I know that the maximum value= -1 but I dont understand how to solve for it. Please Help Me. Thanks in advance for your help and glorious time.
- Kay
Found 2 solutions by jim_thompson5910, robertb:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You are correct. The value of b is since is the same as
So the x coordinate of the vertex is
Plug this back in to get . So the vertex is (0, -1)
So you are correct. The max value is -1.
To solve , plug in y=0 to get
Notice that the quadratic is in the form of where , , and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
or Break up the expression.
or Reduce and simplify
So the solutions are or
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
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