SOLUTION: I know that the fomula x= -b/2a is used to solve for the minimum/maximum value of a quadratic formula but what happens when the quadratic formula is {{{ y= -6x^2-1 }}} a= -6 b=0(?

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Question 341980: I know that the fomula x= -b/2a is used to solve for the minimum/maximum value of a quadratic formula but what happens when the quadratic formula is a= -6 b=0(?) c= -1. I know that the maximum value= -1 but I dont understand how to solve for it. Please Help Me. Thanks in advance for your help and glorious time.
- Kay

Found 2 solutions by jim_thompson5910, robertb:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
You are correct. The value of b is since is the same as


So the x coordinate of the vertex is


Plug this back in to get . So the vertex is (0, -1)


So you are correct. The max value is -1.


To solve , plug in y=0 to get



Notice that the quadratic is in the form of where , , and


Let's use the quadratic formula to solve for "x":


Start with the quadratic formula


Plug in , , and


Square to get .


Multiply to get


Subtract from to get


Multiply and to get .


Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


or Break up the expression.


or Reduce and simplify


So the solutions are or


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim

Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!

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