The second car travels at 15+x

THe first car travels at x

Since its 1 hours less it's

d/(x)=d/(x+15)+1

and d=180

Equation:



Cross mutliply:

180[(15+x)-(x)]=(x+15)(x)





a=1, b=15, c=-2700 in quardatic formula:



simplfy:

x=45 or x=-60

remove the negative and x=45.

Hence, the speed of the first car was 45mph and the second car was 60mph.

Paul. 

RELATED QUESTIONS



Please help me solve THIS problem. A car travels 840 mi. A second car traveling 2 mph  (answered by checkley79)

Please help!

A car travels 304 mi. A second car, traveling 9 mph faster than the first  (answered by ikleyn)

I hope you can help
A car travels 180 miles. A second car, traveling 15 m/h faster than... (answered by solver91311)

A car travels 816 mi. A second car, traveling 3 mph faster than the first car, makes the... (answered by jorel1380)

A car travels 550 mi. A second car, traveling 5 mph faster than the first car, makes the... (answered by jorel1380)

A car travels 840 mi. A second car, traveling 2 mph faster than the first car, makes the... (answered by ankor@dixie-net.com)

A car travels 200 mi. A second car, traveling 10mph faster than the first car, makes the... (answered by TimothyLamb)

A Car travels 240 mi. A second car, traveling 12 mph faster than the first, makes the... (answered by ankor@dixie-net.com)

A car travels 180mi, a second car, traveling 15mi/h faster than the first car , makes the  (answered by Mathtut)