SOLUTION: x^3-3x^2+3x-9=0 I got x=3; x=3i; x=-3i...how do I plug answers back in to check solution?

Question 33912: x^3-3x^2+3x-9=0
I got x=3; x=3i; x=-3i...how do I plug answers back in to check solution?
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
LET Y = x^3-3x^2+3x-9=0
I got x=3; x=3i; x=-3i...how do I plug answers back in to check solution?
HOW DID YOU GET THOSE ANSWERS?...ANY WAY ,YOU HAVE TO JUST SUBSTITUTE THOSE VALUES FOR X AND CHECK
1...X=3...Y=3^3-3*3^2+3*3-9=27-27+9-9=0...OK..
2...X=3i..Y=(3i)^3-3*(3i)^2+3*(3i)-9=27*(i^2)(i)-27(i)^2+9i-9=-27i+27+9i-9=-18i+18...
THIS IS NOT ZERO HENCE THIS IS NOT A ROOT
3...X=-3i..Y=(-3i)^3-3*(-3i)^2+3(-3i)-9=-27(i^2)(i)-27(i^2)-9i-9=27i+27-9i-9=18i+18...
THIS IS NOT ZERO ..HENCE THIS IS NOT A ROOT..
THE CORRECT ANSWERS ARE
X=3
X=i*SQRT(3)
X=-i*SQRT(3)
YOU CAN CHECK BY SUBSTITUTION AS SHOWN ABOVE
RELATED QUESTIONS
(3+ √x)^2+3(3+ √x)-10=0 How do I do this and then plug in solutions to check (answered by Fombitz)

sorry but i'am not sure what this kind of problem is what is x? sqrt (3x+1)+ sqrt... (answered by Alan3354,stanbon)

solve the following equation using the complex number system: x^4 + 13x^2 +36 = 0... (answered by Edwin McCravy)

How to find polynomial with solutions: (0, 2-√3, 3) ? So far I did... (answered by ikleyn,rothauserc)

Is the ordered pair (2,-3) a solution of the equation 8x-3x=7? I got no for the answer... (answered by Alan3354)

Hi I need help with these questions: 1. -9+i/-9-3i I divided the num and dem by (answered by jim_thompson5910)

Which of the following expressions is equal to -3x^2-27 A ) (-3x-3i)(x-9i) B )... (answered by Boreal,math_helper,MathLover1)

Solve for the variable in each equation below. Show all your work. Provide a check for... (answered by Alan3354)

I have a question on polynomials with prescribed zeros. The problem is find polynomial... (answered by ankor@dixie-net.com)