SOLUTION: separate 65 into two parts so that the square of the smaller is 455 less than the square of the larger. what is the answer?
Algebra.Com
Question 339068: separate 65 into two parts so that the square of the smaller is 455 less than the square of the larger. what is the answer?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
separate 65 into two parts so that the square of the smaller is 455 less than the square of the larger. what is the answer?
:
Let x = one part
then
(65-x) = the other part (the larger part)
:
The statement essentially says:
(65-x)^2 - x^2 = 455
;
FOIL (65-x)(65-x)
4225 - 130x + x^2 - x^2 = 455
-130x = 455 - 4225
-130x = -3770
x =
x = +29 is the smaller
and
65 - 29 = 36 is the larger part
:
:
:
See if that's true
36^2 - 29^2 =
1296 - 841 = 455; confirms our solution
RELATED QUESTIONS
Separate 65 into two parts so that 3 times the larger will be 6 more than 6 times the... (answered by stanbon)
Separate 65 into two parts so that 3 times the larger will be 6 more than 6 times the... (answered by KMST)
separate 30 into two parts such that the larger is 6 less than twice the smaller. find... (answered by tommyt3rd)
Separate 45 into two parts such that 5 times the smaller is 6 less than twice the... (answered by Earlsdon)
Separate 65 into two parts such that 3 times the larger will be 6 more than 6 times the... (answered by stanbon)
Separate 45 into 2 parts so that 5 times the smaller number is 6 less than 2 times the... (answered by lwsshak3)
Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger. (answered by edjones)
Can you help me : separate 35 into two parts such that 4 times the larger is 4 less than... (answered by ewatrrr)
The number 15 is divided into two integral parts such that times the square of the... (answered by Alan3354)