SOLUTION: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k � b? (a) -44 (b) -36 (c) 14 (d) 36 (e) 44

SOLUTION: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k � b? (a) -44 (b) -36 (c) 14 (d) 36 (e) 44

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Question 339033: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k � b?
(a) -44 (b) -36 (c) 14 (d) 36 (e) 44

Answer by galactus(183) (Show Source): You can put this solution on YOUR website!
Since the constant in the given quadratic is 16, then k must equal 4.
If k = 4, then we have (5x-4)^2=25x^2-40x+16 and b=-40
Thus, k-b=4-(-40)=44
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