SOLUTION: solve
{{{2t(t+2)=1}}}
I could use some help with this problem please.
Thank you...
Algebra.Com
Question 335768: solve
I could use some help with this problem please.
Thank you...
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2t(t+2)=1
2t^2+4t-1 = 0
------
Quadratic formula:
a = 2 ; b = 4 ; c = -1
---
t = [-b +- sqrt(b^2-4ac)]/(2a)
---------
t = [-4 +- sqrt(16-4*2*-1)]/(2*2)
---------
t = [-4 +- sqrt(16+8)]/4
---------
t = [-4 +- sqrt(24)]/4
---------
t = [-4 +- 2sqrt(6)]/4
---
t = [-2 +- sqrt(6)]/2
========================
Cheers,
Stan H.
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