SOLUTION: How do i work out 16x2-8x+1=0 and also 2x2=4x+1

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Question 334995: How do i work out 16x2-8x+1=0 and also 2x2=4x+1
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Get every term to one side and use the quadratic formula to solve for 'x'. I'll work out the first problem. I'm using this solver


Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=16, b=-8, and c=1




Negate -8 to get 8




Square -8 to get 64 (note: remember when you square -8, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 16 to get 32


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or


which means we only have one solution









Again, if you need more help with the quadratic formula, see this solver

Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
16x^2-8x+1=0
(4x-1)(4x-1)=0
4x-1=0
4x=1
x-1/4 ans.
----------------
2x^2=4x+1
2x^2-4x-1)=0

x=(4+-sqrt[-4^2-4*2*-1])/2*2
x=(4+-sqrt[16+8])/4
x=(4+-sqrt24)/4
x=(4+-4.9)/4
x=4+4.9)/4
x=8.9/4
x=2.25 ans.
x=(4-4.9)/4
x=-.9/4
x=.225 ans.

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