SOLUTION: please help: (3x+2)^2=16

SOLUTION: please help: (3x+2)^2=16

Algebra.Com

Question 331357: please help: (3x+2)^2=16
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(3x+2)^2=16
9x^2+12x+4=18
9x^2+12x+4-18=0
4x^2+12x-14=0
2(x^2+6x-7)=0
2(x+7)(x-1)=0
x+7=0
x=-7 ans.
x-1=0
x=1 ans.
RELATED QUESTIONS
Please help me solve this equation.... (answered by edjones)

please help me solve {{{2^2^(x^2-3)*2^3x=16}}} show that... (answered by Boreal,ikleyn)

Please help solve... (answered by stanbon)

Please help me factor this-please show me the steps 3x^2 + 2x -... (answered by benni1013)

Please help me solve these equations: {{{9x^2-24x+16=0 }}}. (answered by jim_thompson5910)

Please help me find the value of x! (2)^3x =... (answered by ewatrrr,jim_thompson5910)

X^2-3x-4/X^2-16 / 3x+3/X^2+9x+20 please help thank you... (answered by RAY100,jsmallt9)

Can you please help? . Please solve {{{ 64 = 4^(2x) 16^(3x^2) }}}, it is 16 to the... (answered by Alan3354)

show your work please help me with this problem 5 and 2/3x - 16 =... (answered by fractalier)