SOLUTION: please help solve: x^2+3x=4 and 4x^2-3x=-6
... i do not know how to start off these problems..
help please, it is a school assignment.
Algebra.Com
Question 331356: please help solve: x^2+3x=4 and 4x^2-3x=-6
... i do not know how to start off these problems..
help please, it is a school assignment.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2+3x=4
x^2+3x-4=0
(x+4)(x-1)=0
x+4=0
x=-4 ans.
x-1=0
x=1 ans.
------------------
4x^2-3x=-6
4x^2-3x+6=0
X=(3+-SQRT[-3^2-4*4*6])/2*4
X=(3+-SQRT[9-96])/8
X=(3+-SQRT-87)/8
X=(3+-9.327i)/8
X=3/8+-9.327i/8
X=.375+-1.166i
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