SOLUTION: Find the vertex,the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+8

Question 330509: Find the vertex,the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+8
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square to put the equation in vertex form, . where (h,k) is the vertex.

The vertex is (,).
The vertex lies on the axis of symmetry
The max or min value occurs at the vertex.
Since the coefficient for the term is negative, the parabola opens downward and the vertex value is the maximum.

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