SOLUTION: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth.

Question 330488: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth.
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Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let width = x
length = 2x+3
..
ARea = L*W
x(2x+3)=93
2x^2+3x=93
2x^2+3x-93=0
quadratic formula
x1=(-b+sqrt(b^2-4ac))/2a
a=2, b=3, c=-93
x1=(-3+sqrt(9+744))/4
x1= 6.110 cm the width
..
x2=(-3-sqrt(9+744))/4
x2= -7.610 Ignore the negative value
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