SOLUTION: I need help please. I need to solve this problem. (x+10)(x-3)(x+5)>0 Choose correct choice. A. The solution set is {x/what?} (need to fill in for x) or B. The solution is all real

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Question 330255: I need help please. I need to solve this problem. (x+10)(x-3)(x+5)>0 Choose correct choice. A. The solution set is {x/what?} (need to fill in for x) or B. The solution is all real numbers. or C. There is no solution. Thank you.
Found 2 solutions by solver91311, Fombitz:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Step 1: Take each of the factors and set it equal to zero. Solve for for each of them. You will then have 3 boundary numbers.

Step 2: Mark a number line with each of your boundary numbers. You will have divided the real numbers into 4 regions. Negative infinity up to your smallest boundary number, two other regions bounded on both sides, and your largest boundary up to infinity. Note that, because the inequality is as opposed to , NONE of the boundary points will be included in the solution set.

Step 3: From each of the 4 intervals that you have defined, select a value that is NOT one of the boundary points. Substitute that value into the original inequality. If the result is a true statement, include the current interval in the solution set. If the result is false, exclude the current interval. Properly done, your result should be that two of the intervals will be included and two of them excluded.

Step 4: Express your answer as the union of the two included intervals.

John

My calculator said it, I believe it, that settles it


Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!

Break up the number line into 4 regions.
Region 1:( ,)
Region 2:(,)
Region 3:(,)
Region 4:(, )
.
.
Choose a point (not an endpoint) in the region and test the inequality.
Region 1:




False, this region is not part of the solution.
.
.
Region 2:




True, this region is part of the solution.
.
.
Region 3:



False, this region is not part of the solution.
.
.
Region 4:



True, this region is part of the solution.
.
.
(,) U (, )
.
.
.
Graphically look for when the function is above the x-axis.
.
.
.

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