SOLUTION: solve for x providing exact answers using radicals as needed for the following equation x^2+12x+1=36

Question 329015: solve for x providing exact answers using radicals as needed for the following equation x^2+12x+1=36
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve for x providing exact answers using radicals
as needed for the following equation x^2+12x+1=36
-------------------
x^2 + 12x - 35 = 0
---
a = 1 ; b = 12 ; c = -35
----
x = [-12 +- sqrt(144 -4*-35)]/2
---
x = [-12 +- sqrt(284)]/2
---
x = [-12 +- 2sqrt(71)]/2
---
x = [-6 +- sqrt(71)]
===========================
Cheers,
Stan H.
============

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x^2+12x+1=36
x^2+12x+1-36=0
x^2+12x-35=0
find the roots of the equation using formula

a=1b=12c=-35
x = [-12 +- sqrt(144 -4*-35)]/2
..
x = [-12 +- sqrt(284)]/2
..
x = [-12 +- 2sqrt(71)]/2
..
x = [-6 +- sqrt(71)]

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