SOLUTION: y^2=4/5y+4/7= 2 real solutions, one real or two non-real. I say one real because the fractions are opposites of each other? Right? x^2+6x+9=25 solve for x In this equation it asks

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Question 327999: y^2=4/5y+4/7= 2 real solutions, one real or two non-real. I say one real because the fractions are opposites of each other? Right? x^2+6x+9=25 solve for x In this equation it asks for an exact amount.Couldn't I factor this one out to find the value? 9x^2+12x+4 find x and y intercepts At total loss on this one.
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
4/5 and 4/7 are opposites? How?
Either graph the equation or use the discriminant to determine the number of real roots.
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The function crosses the x axis twice, two real roots.
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How many roots? What are they?
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x-intercept: Where does the function cross the x-axis?
y-intercept: Where does the function cross the y-axis? Value for f(x) when x=0.
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You can't factor x out but you can factor two of the equations.
For the first equation, you need to either complete the square or use the quadratic formula.
Equation 2:


Two solutions:
and are the x-intercepts.
is the y-intercept.
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Equation 3:

<--- Double root

is the x-intercept
is the y-intercept

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