SOLUTION: I just don't get word problems! the two sides of a right triangle differ by one. If the hypotenuse is 29cm, then determine the lengths of the two sides. How do I solve using the qu
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Question 324504: I just don't get word problems! the two sides of a right triangle differ by one. If the hypotenuse is 29cm, then determine the lengths of the two sides. How do I solve using the quadratric formula.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"the two sides of a right triangle differ by one" means that the two legs of the triangle are 'x' and 'x+1'
Since "the hypotenuse is 29cm", we know that by the pythagorean theorem, we get the equation
Start with the given equation.
Square 29 to get 841
FOIL
FOIL
Subtract 841 from both sides.
Combine like terms.
Notice that the quadratic is in the form of where , , and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the possible solutions are or
Since a negative length doesn't make sense, this means that we're going to ignore
So this means that one leg is cm long. So the next leg is cm long.
So the lengths of the two legs are 20 cm and 21 cm.
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