SOLUTION: The sum of the squares of two consecutive integers is 613. What are the integers? Let x be one integer. Therefore x +1 is the next integer. x^2+(x+1)^2=613

SOLUTION: The sum of the squares of two consecutive integers is 613. What are the integers? Let x be one integer. Therefore x +1 is the next integer. x^2+(x+1)^2=613

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Question 324085: The sum of the squares of two consecutive integers is 613. What are the integers?
Let x be one integer. Therefore x +1 is the next integer.
x^2+(x+1)^2=613
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Complete the square.

and
.
.
.
The integers are either -18 and -17 or 17 and 18.

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