SOLUTION: f(x)= (x+5)^2-2 The vertex is (ordered pair) the min value is f(x) =

SOLUTION: f(x)= (x+5)^2-2 The vertex is (ordered pair) the min value is f(x) =

Algebra.Com

Question 323624: f(x)= (x+5)^2-2
The vertex is (ordered pair)
the min value is f(x) =
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The equation is in vertex form.
Vertex : (-5,-2)
The minimum value occurs at the vertex since the parabola opens upwards.

RELATED QUESTIONS
one question several parts Graph the function, Find the vertex, line of symmetry,... (answered by Mathtut)

Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic... (answered by robertb)

This is one question with different parts Find the vertex, line of symmetry, maximum or... (answered by solver91311,Mathtut)

What is the ordered pair of the vertex of... (answered by ewatrrr)

Graph the Function. Find the vertex, line of symmetry, and maximum or minimum value. (answered by lwsshak3)

This is 1 question iwth different parts pelase help thank you Find the vertex, line of... (answered by Mathtut,solver91311)

find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by ewatrrr)

find the ordered pair for the vertex f(x)= -(x+5)^2 +9 (answered by stanbon)

f(x)=-3(x+1)^2 The vertex is (ordered pair) the equation of the line of symmetry... (answered by Fombitz)