SOLUTION: x^4-5x^-36=0 How do I solve this.

Question 322829: x^4-5x^-36=0 How do I solve this.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What's the exponent on the 2nd term?
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If it's 2:
It's a quadratic in x^2
x^4-5x^2-36=0
You can factor it.
(x^2 + 4)*(x^2 - 9) = 0
x^2 = 9
x = � 3
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x^2 = -4
x = � 2i
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You can use the quadratic equation.

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=169 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 9, -4. Here's your graph:

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The x given is actually x^2, so see above.

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