SOLUTION: help me solve equation (3x^2+49x+72) in form (3x+ ) (x+ )

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Question 320559: help me solve equation (3x^2+49x+72) in form (3x+ ) (x+ )
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .


Now multiply the first coefficient by the last term to get .


Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?


To find these two numbers, we need to list all of the factors of (the previous product).


Factors of :
1,2,3,4,6,8,9,12,18,24,27,36,54,72,108,216
-1,-2,-3,-4,-6,-8,-9,-12,-18,-24,-27,-36,-54,-72,-108,-216


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to .
1*216 = 216
2*108 = 216
3*72 = 216
4*54 = 216
6*36 = 216
8*27 = 216
9*24 = 216
12*18 = 216
(-1)*(-216) = 216
(-2)*(-108) = 216
(-3)*(-72) = 216
(-4)*(-54) = 216
(-6)*(-36) = 216
(-8)*(-27) = 216
(-9)*(-24) = 216
(-12)*(-18) = 216

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :


First NumberSecond NumberSum
12161+216=217
21082+108=110
3723+72=75
4544+54=58
6366+36=42
8278+27=35
9249+24=33
121812+18=30
-1-216-1+(-216)=-217
-2-108-2+(-108)=-110
-3-72-3+(-72)=-75
-4-54-4+(-54)=-58
-6-36-6+(-36)=-42
-8-27-8+(-27)=-35
-9-24-9+(-24)=-33
-12-18-12+(-18)=-30



From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.


===============================================================



Answer:


So doesn't factor at all (over the rational numbers).


So is prime.


Make sure that you have the correct problem.

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