SOLUTION: find two consecutive positive intergers such that the square of the smaller increased by four times the larger is 64.

SOLUTION: find two consecutive positive intergers such that the square of the smaller increased by four times the larger is 64.

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Question 31338This question is from textbook Mathematics A
: find two consecutive positive intergers such that the square of the smaller increased by four times the larger is 64. This question is from textbook Mathematics A

Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
Let the two consecutive integers be x, and x+1
Equation:
(x)^2+4(x+1)=64
x^2+4x+4=64
x^2+4x-60=0
Factor:
x+10 and x-6
Remove the negative x=6
6+1=7
Hence, the two consecutive integers are 6 and 7.
Paul.

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