SOLUTION: will you please solve this equation? xSquared-7x+5=0(Completing a square)

Question 30991: will you please solve this equation? xSquared-7x+5=0(Completing a square)
Answer by Fermat(136) (Show Source): You can put this solution on YOUR website!
Your eqn is
x� - 7x + 5 = 0
When you square a term like (x+a) you get,
(x+a)� = x� + 2ax + a�
Look at the coefficient of the x-term. It is 2a. Compare that with the coefficient of the x-term in your own eqn. You have: -7.
So equate the coefficient values.
2a = -7
a = -7/2
========
(x+a)� = (x-7/2)� = x� -7x + 7�/2� = x� -7x + 49/4
You've got an extra constant term, 49/4, so add and subtract this to keep your original eqn unaltered.
x� - 7x + 5 = 0 becomes,
x� -7x + 49/4 - 49/4 + 5 = 0
(x-7/2)� -49/4 + 20/4 = 0
(x-7/2)� = 49/4 - 20/4 = 29/4
(x-7/2)� = 29/4
Take the square root of both sides,
(x-7/2) = √29/2
x = 7/2 +/- √29/2
===============
In decimals, that becomes
x = 3.5 +/- 2.6926
x = 6.1926, x = 0.8074
======================
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