SOLUTION: x^4-33x^2-108=0

Algebra.Com
Question 299911: x^4-33x^2-108=0
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
x^4-33x^2-108=0
---
x^4 -36x^2+3x^2-108 = 0
x^2(x^2-36) + 3(x^2-36) = 0
(x^2-36)(x^2+3) = 0
(x-6)(x+6)(x-isqrt(3))(x+isqrt(3)) = 0
x = 6 or x = -6 or x = isqrt(3) or x = -isqrt(3)
=================================================
Cheers,
Stan H.
=================================================

RELATED QUESTIONS

8x^2+33x+4 (answered by Alan3354)
11x^2+33x=0 (answered by Linz)
11x^2+33x=0 (answered by MathLover1)
x^7+28x^6+33x^5+2240x^4+8960x^3+21,504x^2+28,672X+16,384=0 (answered by ikleyn)
33x^2+10x-2=0 (answered by jim_thompson5910)
f (x)= 4x^4 +21x^3 + 33x^2 + 147x +... (answered by MathLover1)
What is the value of x in x^4+33x^2+108x+126=0 Thank u for ur help... (answered by Fombitz)
factor complete : 7x^2 + 33x - 10 =... (answered by jim_thompson5910)
solve the equation: 3x^3 - 26x^2 + 33x +14 = 0 given 2=0 of f(x) = 3x^3 - 26x^2 + 33x +... (answered by stanbon)