SOLUTION: What the fuck is the vertex of x^2-3x-21

Question 297166: What the fuck is the vertex of x^2-3x-21
Found 3 solutions by Alan3354, nyc_function, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
It's on the line of symmetry.
The line of symmetry is x = -b/2a = 3/2
Sub 3/2 for x to find y for the vertex:
y = (3/2)^2 - 3*(3/2) - 21 = -93/4
--> (3/2,-93/4)

Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
Cursing is not allowed on this site.
We first need to find the value of x using x = -b/2a.
In your trinomial, a = 1, b = -3 and c = -21. See it?
We now use a = 1 and b = -3 to find your x value.
x = -(-3)/2(1)
x = 3/2
Now, x = 3/2 is the value of the x-coordinate of your vertex point in the form (x,y).
Understand?
I found x but how do I find y?
Simply replace every x that you see in your trinomial with 3/2 and simplify.
I will set it up and you do the math.
y = (3/2)^2 - 3(3/2) - 21
When you solve for y, you will then have your vertex point in the form (x,y).
Understand?

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
What the fuck is the vertex of x^2-3x-21

My, what language! Use the vertex formula: 1. The x-coordinate of the vertex of is found by evaluating 2. The y-coordinate of the vertex is found by substituting the x-coordinate of the vertex into In your problem , , . Follow the above rules and you'll find that the x-coordinate of the vertex is and the y-coordinate of it is Edwin

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