SOLUTION: Factoring a quadratic with leading coefficient greater than 1
3y^2+7y-6
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Question 295782: Factoring a quadratic with leading coefficient greater than 1
3y^2+7y-6
Found 2 solutions by Fombitz, richwmiller:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
It makes it a little more challenging but the method is the same.
If you FOIL the right hand side you get,
So again look for factor of -6:
(1,-6)
(-1,6)
(2,-3)
(-2,3)
and try to solve for the y-coefficient until you hit the right one.
,
No
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.
,
No
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, and , will give similar results.
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,
No, but we only need to change the signs of a and b for this combination to work.
, .
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
We want factors of -18 which add up to 7
9 and -2
3y^2+9y-2y-6
3y(y+3)-2(y+3)
(3y-2)*(y+3)
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