SOLUTION: I need help in factoring this equation! I also need it to be shown to me step by step because I dont know how to solve it! {{{ 2x^3-x^2-18x+9=0 }}}

Question 293896: I need help in factoring this equation! I also need it to be shown to me step by step because I dont know how to solve it!

Found 2 solutions by jim_thompson5910, unlockmath:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation

Pair off the terms into two groups

Factor out the GCF from the first group.

Factor out the GCF from the second group. The goal is get a common term between the two groups.

Factor out the GCF from the entire left side.

Factor to get using the difference of squares formula.

I'll let you take it from here.
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's first off regroup this 2x^3-x^2-18x+9=0 to give us:
x^2(2x-1)-9(2x-1)=0 From this we have (2x-1) being multiplied by x^2 and -9 so we can use the distributive property to rewrite this as:
(x^2-9)(2x-1)=0 We can factor (x^2-9) to get the following:
(x-3)(x+3)(2x-1)=0 Are you with me so far?
Now we can solve for x to get:
x=3
x=-3
x=1/2
Of course, to check if these are correct, just plug them into the original equation.
Make sense?
RJ
Check out a book I wrote.
www.math-unlock.com
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