SOLUTION: Solve for z, where z is a real number
√(4z+12) = z
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Question 293809: Solve for z, where z is a real number
√(4z+12) = z
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
√(4z+12) = z
4z+12 = z^2
z^2-4z-12=0
(z-6)(z+2)=0
z=6 or z=-2
only answer is z=6
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