SOLUTION: solve using the quadratic formula. round your answer to the nearest hundredth. {{{2x^2-4x-3=0}}} -----here's my try.------ step 1: x=-(-4)±√2^2-4(2)(-3)/2(2) step 2:

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Question 291932: solve using the quadratic formula. round your answer to the nearest hundredth.

-----here's my try.------
step 1: x=-(-4)±√2^2-4(2)(-3)/2(2)
step 2: x=4±√4+24/4
step 3: x=4±√28/4
i don't know what to do past there. please help me, thank you.

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
You should write out the formula and be more clear and not run things together.
You used 2^2 instead of 4^2
you had a^2-4ac

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=40 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.58113883008419, -0.58113883008419. Here's your graph:

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