SOLUTION: Find the vertex of the parabola:
y=-x²+1/2x+2
Algebra.Com
Question 290628: Find the vertex of the parabola:
y=-x²+1/2x+2
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
y=-x^2+(1/2)x+2
y=-(x^2-(1/2)x-2)
y=-(x^2-(1/2)x+1/16-1/16-2)
y=-((x-1/4)^2-1/16-2)
y=-((x-1/4)^2-33/16)
y=-(x-1/4)^2+33/16
Vertex is (1/4, 33/16)
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