SOLUTION: Find the vertex of the parabola:
y=-x²+8x+16
Algebra.Com
Question 290627: Find the vertex of the parabola:
y=-x²+8x+16
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
y=-x^2+8x+16
y=-(x^2-8x-16)
y=-(x^2-8x-16+16-16)
y=-(x^2-8x+16-16-16)
y=-((x-4)^2-16-16)
y=-((x-4)^2-32)
y=-(x-4)^2+32
vertex is (4,32)
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