SOLUTION: You are trying to throw a ball over a wire that is 40 ft above the ground. The height of the ball is modeled by the equation h=-16t^2 + 40t + 6. Will you be able to throw the ball

Question 286293: You are trying to throw a ball over a wire that is 40 ft above the ground. The height of the ball is modeled by the equation h=-16t^2 + 40t + 6. Will you be able to throw the ball over the wire?
Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
plug 40 in as h
and solve for t
only complex numbers for solutions
31 is the max for h=-16t^2 + 40t + 6
the vertex is (31, 1.25)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
You are trying to throw a ball over a wire that is 40 ft above the ground.
The height of the ball is modeled by the equation h=-16t^2 + 40t + 6.
Will you be able to throw the ball over the wire?
:
Find the max height:
the axis of symmetry;
t =
t = 1.25 secs
:
Find the max height
h = -16(1.25^2) + 40(1.25) + 6
h = -16(1.5625) + 50 + 6
h = -25 + 56
h = 31 ft, the answer is no
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