SOLUTION: i need more than 1 problem please. heres the problems:
evaluate: 3a + (k + 5b) - 9=? if a=7 & b=4 & k=10
find the 7th term in the sequence: 20 1/2, 23 1/3, 26 1/6 29...
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Algebra.Com
Question 285653: i need more than 1 problem please. heres the problems:
evaluate: 3a + (k + 5b) - 9=? if a=7 & b=4 & k=10
find the 7th term in the sequence: 20 1/2, 23 1/3, 26 1/6 29...
evaluate: -6a-4b= ? if a=5 and b=3??
please! thanks
Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
evaluate: 3a + (k + 5b) - 9=? if a=7 & b=4 & k=10
3*7 + (10 + 5*4)
21 + (10+20)
21 + 30
51
----------------------------
find the 7th term in the sequence: 20 1/2, 23 1/3, 26 1/6 29...
----------------------------
evaluate: -6a-4b= ? if a=5 and b=3
-6*5 - 4*3
-30 - 12
-42
--------------------------------------
Cheers,
Stan H.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
The rules are very clear one problem at a time not two not three.
Not only that but the rules also say no similar problems.
Why do you think you can ignore the rules? Because you put a whining please?
Also limit yourself to 4 problems sent separately per day.
Believe it or not because you hogged Stan's time for three problems, two people with real problems will not get their problems answered. Is that fair?
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