SOLUTION: Write a quadratic equation having the given numbers as solutions. -3.5, 2.2

Question 281364: Write a quadratic equation having the given numbers as solutions. -3.5, 2.2

Found 2 solutions by oberobic, graphmatics:
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The general form of a quadratic equation that has been solved is to have two factors that are multiplied. In this case, you're told the solutions are x= -3.5 and x=2.2. So the factored form of the equation would be:
.
(x + 3.5)(x - 2.2) = 0
.
Using FOIL...
.
x^2 -2.2x +3.5x -7.7 = 0
x^2 + 1.3x - 7.7 = 0
.
multiply by 10 to get rid of the decimals...
.
10x^2 + 13x - 77 = 0
.
Checking this equation using the quadratic formula, you can determine if the solutions are x= -3.5 and x= 2.2...
.
.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3249 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.2, -3.5. Here's your graph:

.
Done
Answer by graphmatics(170) (Show Source): You can put this solution on YOUR website!
(x+3.5)(x-2.2)
x**2+3.5x-2.2x-7.7
x**21.1x-7.7
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