Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=0 is zero! That means that there is only one solution: Expression can be factored: Again, the answer is: -2, -2. Here's your graph: |
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=16 is greater than zero. That means that there are two solutions: Quadratic expression Again, the answer is: 3, -1. Here's your graph: |
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant The discriminant -8 is less than zero. That means that there are no solutions among real numbers. If you are a student of advanced school algebra and are aware about imaginary numbers, read on. In the field of imaginary numbers, the square root of -8 is + or - The solution is Here's your graph: |