SOLUTION: Can someone help me please? How do I figure out how many solutions there are to this equation? x2 + 4x + 4 = 0

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Question 278851: Can someone help me please?
How do I figure out how many solutions there are to this equation?
x2 + 4x + 4 = 0
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x^2+4x+4=0
has two solutions since x^2 has two roots or solutions
(x+2)^2=0
but the two solutions are equal.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: -2, -2. Here's your graph:
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