SOLUTION: Chuck throws a rock with an initial upward velocity of 12m/sec. How high is it after 0.7 seconds?

Question 275286: Chuck throws a rock with an initial upward velocity of 12m/sec. How high is it after 0.7 seconds?
Found 2 solutions by nerdybill, Greenfinch:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Chuck throws a rock with an initial upward velocity of 12m/sec. How high is it after 0.7 seconds?
.
y = (1/2)at^2 + vt
where
'y' is the height
'a' is gravity -9.8 m/sec^2
v is initial velocity
t is time
.
y = (1/2)(-9.8)(0.7)^2 + (12)(0.7)
y = (-4.9)(.49) + 8.4
y = 6 m
Answer by Greenfinch(383) (Show Source): You can put this solution on YOUR website!
u = 12
a = -9.8
t = 0.7
s = ?
s = ut + 1/2(at^2)
s = 12x0.7 + 1/2x(-9.8)x0.49
s = 8.4 - 1.2
s = 7.2 m
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