SOLUTION: If {{{f(x)=4x^2+7x+2}}} Find the following: f(x)<0 f(x)>0

Question 273993: If
Find the following:
f(x)<0

f(x)>0
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
f(x)=4x^2+7x+2
4x^2+7x+2=0
x=(-7-sqrt(17))/8, x=(-7+sqrt(17)) see below
f(x)<0 ((-7-sqrt(17))/8) f(x)>0 ((-7-sqrt(17))/8)>x>((-7+sqrt(17))/8)
.
Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=17 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -0.359611796797792, -1.39038820320221. Here's your graph:

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