SOLUTION: Please help me solve this equation: {{{y=x^2-4}}} I need to find the x intercept and the y intercept and also the vertex. I am struggling mostly with finding the x intercept.

Question 272938: Please help me solve this equation:
I need to find the x intercept and the y intercept and also the vertex. I am struggling mostly with finding the x intercept.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation:
I need to find the x intercept and the y intercept and also the vertex. I am struggling mostly with finding the x intercept.
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To find the x-intercept let y = 0 and solve for "x":
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x^2-4 = 0
(x-2)(x+2) = 0
x = 2 or x=-2 (these are the x-intercepts.
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Vertex ?
You have a quadratic with a = 1, b = 0, c = -4
The vertex occurs at x = -b/2a = -0/2 = 0.
When x = 0, y = 0^2-4 = -4
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Vertex: (0,-4)
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Cheers,
Stan H.
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