SOLUTION: write a quadratic equation with integral coefficients and roots equal to 2/3 and -1/2
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Question 272459: write a quadratic equation with integral coefficients and roots equal to 2/3 and -1/2
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
In general, a quadratic equation may be depicted as y = (x + j)(x + k), where j & k are numbers. The roots of the equation will be the value of x that make x+j = 0 and the value of x that makes x+k = 0.
So, we want the roots to be 2/3 and -1/2, which means:
y = (x-2/3)(x+1/2)
Notice the signs are reversed so the roots will be the value indicated.
Multiplying through, we have
y = x^2 + 1/2x - 2/3x -2/6
y = x^2 + 3/6x - 4/6x - 2/6
y = x^2 - 1/6x - 2/6
.
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