SOLUTION: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t)=-16t^2+64, where t is the number of seconds after it is dropped.
Find h(1).
How
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Question 271959: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t)=-16t^2+64, where t is the number of seconds after it is dropped.
Find h(1).
How long does it take the ball to fall to the earth?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A ball is dropped from a height of 64 feet.
Its height above the earth in feet is given by h(t)=-16t^2+64, where t is the number of seconds after it is dropped.
Find h(1) = -16 + 64 = 48 ft
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How long does it take the ball to fall to the earth?
The height will be zero at that time.
Solve -16t^2+64 = 0
-16t^2 = -64
t^2 = 4
Positive solution:
t = 2 seconds
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Cheers,
Stan H.
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