SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
So, um yeah I don't get this one at all.
Algebra.Com
Question 27097: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
So, um yeah I don't get this one at all.
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
LEt the three integers be x, x+2 and x+4
x=16
16+2=18
16+4=20
Hence, the three consecutive integers are 16, 18 and 20.
Paul.
RELATED QUESTIONS
Three consecutive even integers are such that the square of the third is 76 more than the (answered by venugopalramana)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by Nate)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by ankor@dixie-net.com)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by jmichau3)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by checkley75)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by solver91311)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by nerdybill)
Three consecutive even integers are such that the square of the third is 76 more than the (answered by checkley77)
Solve the following problems involving applications of polynomials.
Three consecutive... (answered by ankor@dixie-net.com)