SOLUTION: (x^2)^2-7x^2-8=0

Question 269533: (x^2)^2-7x^2-8=0
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Let Y = x^2 and Y^2 = x^4. We get
Y^2 - 7Y - 8 = 0
factoring, we get
(Y-8)(Y+1) = 0
solving each for Y, we get
Y = 8 and
Y = -1
re-substitute x^2 for Y and we get
x^2 = 8 - - - > X = 2sqrt(2)
x^2 = -1 - - -> no solution
RELATED QUESTIONS
x^2-7x-8=0 (answered by Fombitz)

x^2+7x-8=0 (answered by solver91311)

X^2-7x=0 (answered by ikleyn)

Solve x^2 + 7x + 8 =... (answered by MathLover1)

2=x-7x+8 (answered by oscargut)

2 X +... (answered by chitra)

x^2+7x+10=0 (answered by tutorcecilia)

x^2-7x-30=0 (answered by stanbon)

x^2-7x+10=0 (answered by edjones)