SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=1/5(x+2)^2+8

Question 266719: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=1/5(x+2)^2+8
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=(1/5)(x+2)^2+8
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Vertex: (-2,8)
Axis of symmetry: x = -2
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Minimum value of f(x): f(x) = 8
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Cheers,
Stan H.
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