SOLUTION: My book says the answer is -5 and -3, where am I missing it? {{{x^2-8x-15=0}}} x={{{(-(-8)+- sqrt(-8^2-4*1*15))/(2*1)}}} x={{{8+- sqrt (64-60)/(2)}}} x={{{8+- sqrt (4)/(2)}}}

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Question 259972: My book says the answer is -5 and -3, where am I missing it?

x=
x=
x=
x=
x=

Found 2 solutions by ankor@dixie-net.com, Edwin McCravy:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
My book says the answer is -5 and -3, where am I missing it?
, assume the equation should be x^2 - 8x + 15
x=
x=
x=
:
Th book is wrong, this would factor to:
(x-5)(x-3) = 0
which is:
x=5,x=3

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

I think you aren't being careful with your signs and
with putting parentheses around what you are substituting.
If your book says the solutions are -5 and -3, then you 
have typed one or two signs wrong in the original problem, 
or else the book has a typographical error, and sometimes 
they do.

You gave the problem as



but the solutions to that are not -5 and -3.

You would have to have had this problem instead

  [not  as the other tutor said.]

In order to get solutions -5 and -3.

Then you would factor and get



and then you'd set each of those = 0 and get

x+5=0      x+3=0
  x=-5       x=-3


But let's suppose it was as you thought

You have this:


x=
x=
x=
x=
x=

Then you'd factor 2 out of the top:

x=

and then cancel the 2's

x=



Edwin


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