SOLUTION: f(x)=-x^2+12x+3 find the vertex(ordered pair): find line of symmetry: maximum/minimum of f(x) is: the value f(6)=39 is which of the following maximum or minimum:

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Question 259276: f(x)=-x^2+12x+3
find the vertex(ordered pair):
find line of symmetry:
maximum/minimum of f(x) is:
the value f(6)=39 is which of the following maximum or minimum:

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
f(x)=-x^2+12x+3
you seem to repeat yourself.
The vertex is the max/min. This one has a max at (6,39) which is f(6)=39
so that is three times you ask for the vertex and/or max
All parabolas are symmetric with respect to a line called the axis of symmetry. A parabola intersects its axis of symmetry at a point called the vertex of the parabola.
so that makes four times
The graph doesn't show it well but the peak (vertex is off to the right at 6,39
with x=6 the line of symmetry
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=156 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.244997998398398, 12.2449979983984. Here's your graph:

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