SOLUTION: This is actually solving a problem that is quadratic in form. I am having lots of difficulties trying to figure this one out trying to substitute, but even sure if that is what I a

Question 258790: This is actually solving a problem that is quadratic in form. I am having lots of difficulties trying to figure this one out trying to substitute, but even sure if that is what I am supposed to do and totally stumped. Here is the problem:
(x-3)^2/5=(4x)^1/5
If I let u = (x-3)^1/3, it still doesn't quite make it into a quadratic as it then looks like:
u^2=(4x)^1/5
This is where I am stumped, not sure how to proceed after this since I can't use u to equal the 4x also as they are not like terms.
(and the exponents are fractions)
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Raise both sides to the 5th power.
Multiply the exponents on the inside of the parentheses by those on the outside.
Simplify.
Subtract 4x from both sides.
Factor this quadratic equation.
Apply the zero product rule.
or so...
or
Caution! Check the solutions by substituting into the given equation to discover any possible "extraneous" solutions..
Substitute x = 1.
Evaluate using a calculator.

OK for x=1.
Substitute x = 9.
Evaluate.

OK for x = 9
Both solutions are valid!
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