SOLUTION: How do I solve this problem f(x) = -0.3x^2 + 25x + 16 using the quadratic formula and graphing...I'm lost. I know x = 1 if this helps.

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Question 258234: How do I solve this problem f(x) = -0.3x^2 + 25x + 16 using the quadratic formula and graphing...I'm lost. I know x = 1 if this helps.
Found 2 solutions by richwmiller, stanbon:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
No x does not equal 1
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=644.2 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.635158878390421, 83.9684922117238. Here's your graph:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
How do I solve this problem f(x) = -0.3x^2 + 25x + 16 using the quadratic formula and graphing
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You use the quadratic formula to find roots or zeroes of the equation.
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-0.3x^2 + 25x + 16 = 0
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x = [-25 +- sqrt(25^2 - 4*-0.3*16)]/(2*-0.3)
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x = [-25 +- sqrt(625 + 19.2)]/(-0.6)
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x = [-25 + 25.3811]/(-0.6) or x = [-50.3811]/(-0.6) = 83.97
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x = 0.3811/(-0.6) = -0.6352... or x = 83.97..
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Cheers,
Stan H.
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