SOLUTION: Consider the equation with the formula y=x squared+6x-1 A)find the values of x when y=0 B) find the vertex of the parabola C) graph the parabola and d) give the line of symm

Question 25661: Consider the equation with the formula y=x squared+6x-1 A)find the values of x when y=0 B) find the vertex of the parabola C) graph the parabola and d) give the line of symmentry
I believe for part B i first must get the formula into vertex form and that should help me with the rest of the parts to the question but for part A, I do not understand how i would answer with the qaudratic Formula. Would it be -6 plus or minus the square root of 6 squared - 4*a*c over 2*a ?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y=x^2+6x-1
A) Let y=0:
x^2+6x-1=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=40 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.16227766016838, -6.16227766016838. Here's your graph:

B) Complete the square:
y= (x^2+6x+9)-1-9
y=(x+3)^2-10
y+10=(x+3)^2
This is in "vertex" form:
h=-3, k=-10
C) The axis of symmetry is x=-3
Cheers,
Stan H.

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