SOLUTION: I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Can someone ple

Algebra.Com
Question 256296: I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Can someone please show me the steps to get to the answer? Thank you.
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
Let the numbers be x, x+1 and x+2.
x(x+1)-3(x+2)=57
x^2+x-3x-6=57
x^2-2x-6=57
x^2-2x-63=0
(x-9)(x+7)=0
x=9, x=-7 Two different sets of correct answers: 9, 10, 11 and -7, -6, -5
.
Ed

RELATED QUESTIONS

I am thinking of three consecutive negative numbers. If I multiply the first with the... (answered by solver91311)
I am thinking of three consecutive numbers. If I multiply the first with the second and... (answered by nabla)
I am thinking of three consecutive negative numbers. If I multiply the first with the... (answered by sowmya)
I am thinking of three consecutive negative numbers. If i multiply the first with the... (answered by stanbon)
I am thinking of three consecutive numbers. If I multiply the first with the second and... (answered by Grinnell)
I am thinking of three consecutive negative numbers. If I multiply the first with the... (answered by stanbon)
(((I am thinking of three consecutive numbers. If I multiply the first with the second... (answered by stanbon)
Here is a word problem I am having trouble figuring out: "I am thinking of three... (answered by user_dude2008)
I am thinking of three consecutive negative numbers. If I multiply the first with the... (answered by checkley77)